• kevinbealer yahoo.com May 03 2004
• Andy Friesen <andy ikagames.com> May 03 2004
• Kevin Bealer <Kevin_member pathlink.com> May 04 2004
• Ben Hinkle <bhinkle4 juno.com> May 03 2004
• Mike Wynn <one_mad_alien hotmail.com> May 06 2004

kevinbealer yahoo.com writes:

Let's say I want to define a mutable string:

char[] a_tmp = "abcd";  // immutable ref
char[] a;
a[] = a_tmp; // mutable copy of immutable data.

OR..?

char[] a = "abc" ~ "d";

Is there a simpler or more direct syntax?

Kevin

Andy Friesen <andy ikagames.com> writes:

kevinbealer yahoo.com wrote:
 Let's say I want to define a mutable string:
 
 char[] a_tmp = "abcd";  // immutable ref
 char[] a;
 a[] = a_tmp; // mutable copy of immutable data.
 
 OR..?
 
 char[] a = "abc" ~ "d";
 
 Is there a simpler or more direct syntax?
 
 Kevin
 
 


char[] a = ("abcd").dup; may work for you.

  -- andy

Kevin Bealer <Kevin_member pathlink.com> writes:

In article <c76g4e$iau$1 digitaldaemon.com>, Andy Friesen says...
kevinbealer yahoo.com wrote:
 Let's say I want to define a mutable string:
 
 char[] a_tmp = "abcd";  // immutable ref
 char[] a;
 a[] = a_tmp; // mutable copy of immutable data.
 
 OR..?
 
 char[] a = "abc" ~ "d";
 
 Is there a simpler or more direct syntax?
 
 Kevin
 
 


char[] a = ("abcd").dup; may work for you.

  -- andy


Yep, that looks like the most logical.

Kevin

Ben Hinkle <bhinkle4 juno.com> writes:

kevinbealer yahoo.com wrote:

 Let's say I want to define a mutable string:
 
 char[] a_tmp = "abcd";  // immutable ref
 char[] a;
 a[] = a_tmp; // mutable copy of immutable data.
 
 OR..?
 
 char[] a = "abc" ~ "d";
 
 Is there a simpler or more direct syntax?
 
 Kevin


The ".dup" property will duplicate an array:
 char[] a = a_tmp.dup;

Mike Wynn <one_mad_alien hotmail.com> writes:

On Mon, 3 May 2004 22:05:57 +0000 (UTC), kevinbealer yahoo.com wrote:

Let's say I want to define a mutable string:

char[] a_tmp = "abcd";  // immutable ref
char[] a;
a[] = a_tmp; // mutable copy of immutable data.

OR..?

char[] a = "abc" ~ "d";

Is there a simpler or more direct syntax?

Kevin


---------------------
import std.c.stdio;

void nctest() {
	char[] a = "abcd";
	char[]b = a;
 	printf( "char[] a = 'acbd'\n" );
 	printf( "char[] b = a;\n=>\n" );
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
 	printf( "b[2]='2'...\n" );
 	b[2] = '2';
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
}
void ctest() {
	const char[] a = "abcd";
	char[]b = a;
 	printf( "const char[] a = 'acbd'\n" );
 	printf( "char[] b = a;\n=>\n" );
 	printf( "b[2]='2'...\n" );
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
 	printf( "b[2]='2'...\n" );
 	b[2] = '2';
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
}

int main( char[][] args ) {
	nctest();
	ctest();
	return 0;
}
------------------------
output (as one would hope is)
char[] a = 'acbd'
char[] b = a;
=>
a=abcd
b=abcd
b[2]='2'...
a=ab2d
b=ab2d
const char[] a = 'acbd'
char[] b = a;
=>
b[2]='2'...
a=abcd
b=abcd
b[2]='2'...
a=abcd
b=ab2d