digitalmars.D - Suggestion: Templated polymorphic functions
- Oskar Linde <oskar.lindeREM OVEgmail.com> Nov 20 2005
- Don Clugston <dac nospam.com.au> Nov 22 2005
Hi,
Contrary to how the subject may sound, this is a suggestion for a small change
in implicit template parameters. The spec says:
"If a template has exactly one member in it, and the name of that member is the
same as the template name, that member is assumed to be referred to in a
template instantiation"
I suggest an addition. Something like:
"If a template only has function members, all of which have the same name as the
template, those are assumed to be referred to in a template instantiation."
Consider the following (nonsense) template defining a bunch of polymorphic
functions:
# template foo(T) {
# T foo(int x) { return 1; }
# T foo(double x) { return 2; }
# }
Those functions would then be accessed with eg. foo!(int). Eg:
foo!(int)(5) returns 1, foo!(int)(1.0) returns 2.
---
The reason I bumped into this was trying to implement array conversion
functions:
# template conv(S:S[],D:D[]) {
# D[] conv(S[] src) {
# D[] dst;
# dst.length = src.length;
# foreach(int i, S s; src)
# dst[i] = cast(D) s;
# return dst;
# }
# }
And then using a "templated typedef" for all basic types:
# template to(D:D[]) {
# alias conv!(int[],D[]) to;
# alias conv!(double[],D[]) to;
# // etc...
# }
Allowing:
# const double[] x = [1.5,2.5,-0.9];
# int[] y = to!(int[])(x); // Doesn't compile. Needs to!(int[]).to(x);
(Ideally, I would like the syntax x.to!(int[]) to work, but this doesn't
work at all for templated functions. I may attend to this in a separate post.)
---
Concerning Implicit Template Properties:
I'm feeling slightly uncomfortable with the rule that removes the extra scope
level when the template and a single parameter has the same name. Wouldn't it
be better instead to make this explicit using the 'this' keyword:
# template something(T) {
# T this(int x) {return 5;}
# }
# template SomethingElse(T) {
# class this {
# T x,y;
# }
# }
---
Comments?
/Oskar
Nov 20 2005
Oskar Linde wrote:Hi, Contrary to how the subject may sound, this is a suggestion for a small change in implicit template parameters. The spec says: "If a template has exactly one member in it, and the name of that member is the same as the template name, that member is assumed to be referred to in a template instantiation" I suggest an addition. Something like: "If a template only has function members, all of which have the same name as the template, those are assumed to be referred to in a template instantiation." Consider the following (nonsense) template defining a bunch of polymorphic functions: # template foo(T) { # T foo(int x) { return 1; } # T foo(double x) { return 2; } # } Those functions would then be accessed with eg. foo!(int). Eg: foo!(int)(5) returns 1, foo!(int)(1.0) returns 2.
That makes sense, but be aware that right now, even this doesn't work: template foo(T) { static if (1) { T foo(int x) { return 1; } } } int x = foo!(int)(5); // No, must use foo!(int).foo(5); Walters indicated he's probably going to change this. But I hope that it would still work, even in extreme cases like: template foo(T) { static if (is (T : int) ) { int foo(int x) { return 1; } } else { struct foo { T s; } } } And if that worked, your suggestion might work too.Concerning Implicit Template Properties: I'm feeling slightly uncomfortable with the rule that removes the extra scope level when the template and a single parameter has the same name. Wouldn't it be better instead to make this explicit using the 'this' keyword: # template something(T) { # T this(int x) {return 5;} # } # template SomethingElse(T) { # class this { # T x,y; # } # }
I definitely like the idea -- but does it work? What happens when you need to use the 'this' pointer? How do you distinguish between the class and the instance? class this { this() {} this somefunc(this a) { this = a; return a.b==1 ? this : new this; } } Another possibility might be to use the return keyword at the start of the declaration. I would definitely be interested in something like one of these, if it was possible to prevent it from automatically triggering in template alias parameters (and if there was a way of triggering it later). template t(alias a) { void f() { writefln(typeid(a).typeof); } } template s(Z) { Z s(int q) { return 1; } } t!(s!(int)) ---> a is s!(int).s(), but I want it to pass s!(int) and later I want to invoke s!(int).s(3) I just feel that at the moment, some aspects of the language are too incomplete for the implicit template properties to really work well, right now it can be more of a nuisance.
Nov 22 2005








Don Clugston <dac nospam.com.au>