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c++ - Explicit template argument specification for member templates

reply Christof Meerwald <cmeerw web.de> writes:
Here is a test-case:

struct A
{
  template<typename T>
  int f(T t)
  {
    return T::val;
  }

  template<typename T>
  int g()
  {
    return T::val;
  }
};

struct B
{
  static const int val = 0;
};


int main()
{
  A a;
  B b;

  return a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
  // Error: '(' expected following simple type name
}


bye, Christof

-- 
http://cmeerw.org                                 JID: cmeerw jabber.at
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...and what have you contributed to the Net?
Nov 24 2002
next sibling parent "Neo" <newneo2 yahoo.com> writes:
i think that's because extra wrong directed information
it's like u r parametizing the function in advance and parameter in function
may be different and it may create conflict, and hence error is perfectly
right

"Christof Meerwald" <cmeerw web.de> wrote in message
news:arqv16$eqp$1 digitaldaemon.com...

 Here is a test-case:

 struct A
 {
   template<typename T>
   int f(T t)
   {
     return T::val;
   }

   template<typename T>
   int g()
   {
     return T::val;
   }
 };

 struct B
 {
   static const int val = 0;
 };


 int main()
 {
   A a;
   B b;

   return a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
   // Error: '(' expected following simple type name
 }


 bye, Christof

 --
 http://cmeerw.org                                 JID: cmeerw jabber.at
 mailto cmeerw at web.de

 ...and what have you contributed to the Net?
Nov 28 2002
prev sibling parent reply Christof Meerwald <cmeerw web.de> writes:
Still doesn't work if the program is slightly modified.

On Sun, 24 Nov 2002 16:33:42 +0000 (UTC), Christof Meerwald wrote:

 Here is a test-case:
 
 struct A
 {
   template<typename T>
   int f(T t)
   {
     return T::val;
   }
 
   template<typename T>
   int g()
   {
     return T::val;
   }
 };
 
 struct B
 {
   static const int val = 0;
 };
 
 
 int main()
 {
   A a;
   B b;
 
   return a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
   // Error: '(' expected following simple type name



  int i = a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
  int j = a.f<C>(c) + a.f<>(c) + a.f(c) + a.g<C>();
  // Error: 'A::g' is already defined


 }




bye, Christof

-- 
http://cmeerw.org                                 JID: cmeerw jabber.at
mailto cmeerw at web.de

...and what have you contributed to the Net?
Jan 06 2003
parent Christof Meerwald <cmeerw web.de> writes:
Oops, missed the definition of C:

On Mon, 6 Jan 2003 19:23:56 +0000 (UTC), Christof Meerwald wrote:

 Still doesn't work if the program is slightly modified.
 
 On Sun, 24 Nov 2002 16:33:42 +0000 (UTC), Christof Meerwald wrote:

 Here is a test-case:
 
 struct A
 {
   template<typename T>
   int f(T t)
   {
     return T::val;
   }
 
   template<typename T>
   int g()
   {
     return T::val;
   }
 };
 
 struct B
 {
   static const int val = 0;
 };






struct C
{
  static const int val = 1;
};


 int main()
 {
   A a;
   B b;
 
   return a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
   // Error: '(' expected following simple type name



   int i = a.f<B>(b) + a.f<>(b) + a.f(b) + a.g<B>();
   int j = a.f<C>(c) + a.f<>(c) + a.f(c) + a.g<C>();
   // Error: 'A::g' is already defined
 

 }







bye, Christof

-- 
http://cmeerw.org                                 JID: cmeerw jabber.at
mailto cmeerw at web.de

...and what have you contributed to the Net?
Jan 07 2003