• J Anderson <REMOVEanderson badmama.com.au> Dec 18 2003
• Patrick Down <pat codemoon.com> Dec 18 2003
• J Anderson <REMOVEanderson badmama.com.au> Dec 18 2003

With the for each val is always a copy, which means code like below is 
incorrect.

int [] array;

foreach (int i, int val; array)
{
    val = 10;
}

I think in foreach val should be a reference. 

What's worse, is if you iterate through an array of structs with 
foreach.  In these cases there probably is a  performance hit due to the 
copy.

-Anderson

You can do it with inout

J Anderson <REMOVEanderson badmama.com.au> wrote in
news:brsd95$9iu$1 digitaldaemon.com: 

 With the for each val is always a copy, which means code like below is
 incorrect.
 
 int [] array;
 
 foreach (int i, int val; array)
 {
     val = 10;
 }


foreach (inout int i, int val; array)
{
     val = 10;
}



 
 I think in foreach val should be a reference. 
 
 What's worse, is if you iterate through an array of structs with 
 foreach.  In these cases there probably is a  performance hit due to
 the copy.
 
 -Anderson
 
 

Patrick Down wrote:

You can do it with inout
  


Thanks.

J Anderson <REMOVEanderson badmama.com.au> wrote in
news:brsd95$9iu$1 digitaldaemon.com: 

  

With the for each val is always a copy, which means code like below is
incorrect.

int [] array;

foreach (int i, int val; array)
{
    val = 10;
}
    


foreach (inout int i, int val; array)
{
     val = 10;
}



  

I think in foreach val should be a reference. 

What's worse, is if you iterate through an array of structs with 
foreach.  In these cases there probably is a  performance hit due to
the copy.

-Anderson