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D - A bug, feature or misunderstanding?

reply Gennadi Pais <Gennadi_member pathlink.com> writes:
Hi All,
during my first trying of the D language in the code:

char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);

I received compiler error:
.. undefined identifier append

Compiler is: Digital Mars D Compiler Beta v0.68

The tested code is from the D spec.
Thanks.
Aug 05 2003
next sibling parent reply "Matthew Wilson" <matthew stlsoft.org> writes:
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.

Aug 05 2003
parent reply Gennadi Pais <Gennadi_member pathlink.com> writes:
That's the way I implemented it, but what about the spec?

In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.


Aug 05 2003
parent reply "Matthew Wilson" <matthew stlsoft.org> writes:
Sorry, I don't understand. In your example you said you done "%s", whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out of
my jurisdiction, I'm afraid. ;)

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
 That's the way I implemented it, but what about the spec?

 In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.



Aug 05 2003
parent reply Gennadi Pais <Gennadi_member pathlink.com> writes:
Please pay attention to the next cut from the D's spec (Arrays section):
______________________________
There are two ways to use printf() with D strings. The first is to add a
terminating 0, and cast the result to a char*: 

str.append(0);
printf("the string is '%s'\n", (char *)str);

The second way is to use the precision specifier. The way D arrays are laid out,
the length comes first, so the following works: 

printf("the string is '%.*s'\n", str);
______________________________
I just want to say that the first described above way is not compiled and failed
with an error (see my first message).

In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s", whereas
I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out of
my jurisdiction, I'm afraid. ;)

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
 That's the way I implemented it, but what about the spec?

 In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.




Aug 05 2003
parent reply "Matthew Wilson" <matthew stlsoft.org> writes:
I may be missing something here - possible - but you seem to be
contradicting yourself.

Your first example was

char[] str = "blah-blah";
str.append(0);
printf ("str is: %s\n", str);

Now in this you do neither of

  printf ("str is: %s\n", (char*)str);

or

  printf ("str is: %.*s\n", (char*)str);


Surely this is clear?


"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgoe7f$1b2c$1 digitaldaemon.com...
 Please pay attention to the next cut from the D's spec (Arrays section):
 ______________________________
 There are two ways to use printf() with D strings. The first is to add a
 terminating 0, and cast the result to a char*:

 str.append(0);
 printf("the string is '%s'\n", (char *)str);

 The second way is to use the precision specifier. The way D arrays are

 the length comes first, so the following works:

 printf("the string is '%.*s'\n", str);
 ______________________________
 I just want to say that the first described above way is not compiled and

 with an error (see my first message).

 In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",


I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out


my jurisdiction, I'm afraid. ;)

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
 That's the way I implemented it, but what about the spec?

 In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.





Aug 05 2003
parent reply "Matthew Wilson" <matthew stlsoft.org> writes:
Correction, the two examples I meant were

   printf ("str is: %s\n", (char*)str);

or

   printf ("str is: %.*s\n", str);




"Matthew Wilson" <matthew stlsoft.org> wrote in message
news:bgp97g$272e$1 digitaldaemon.com...
 I may be missing something here - possible - but you seem to be
 contradicting yourself.

 Your first example was

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 Now in this you do neither of

   printf ("str is: %s\n", (char*)str);

 or

   printf ("str is: %.*s\n", (char*)str);


 Surely this is clear?


 "Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
 news:bgoe7f$1b2c$1 digitaldaemon.com...
 Please pay attention to the next cut from the D's spec (Arrays section):
 ______________________________
 There are two ways to use printf() with D strings. The first is to add a
 terminating 0, and cast the result to a char*:

 str.append(0);
 printf("the string is '%s'\n", (char *)str);

 The second way is to use the precision specifier. The way D arrays are

 the length comes first, so the following works:

 printf("the string is '%.*s'\n", str);
 ______________________________
 I just want to say that the first described above way is not compiled


 failed
 with an error (see my first message).

 In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",


I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out


my jurisdiction, I'm afraid. ;)

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
 That's the way I implemented it, but what about the spec?

 In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.






Aug 05 2003
parent Gennadi Pais <Gennadi_member pathlink.com> writes:
Dear All,
thank for the explanation how can I print a string out, but if you will pay
attention I didn't ask about how to (I've found some different ways), but the
issue was the compilation error because of lack of the array's <append> method.
I think the clear and right spec is exactly what the new language need. So I
want to ask somebody who has permission to edit D's documentation to fix that
over there.

In article <bgpb2f$28tu$1 digitaldaemon.com>, Matthew Wilson says...
Correction, the two examples I meant were

   printf ("str is: %s\n", (char*)str);

or

   printf ("str is: %.*s\n", str);




"Matthew Wilson" <matthew stlsoft.org> wrote in message
news:bgp97g$272e$1 digitaldaemon.com...
 I may be missing something here - possible - but you seem to be
 contradicting yourself.

 Your first example was

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 Now in this you do neither of

   printf ("str is: %s\n", (char*)str);

 or

   printf ("str is: %.*s\n", (char*)str);


 Surely this is clear?


 "Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
 news:bgoe7f$1b2c$1 digitaldaemon.com...
 Please pay attention to the next cut from the D's spec (Arrays section):
 ______________________________
 There are two ways to use printf() with D strings. The first is to add a
 terminating 0, and cast the result to a char*:

 str.append(0);
 printf("the string is '%s'\n", (char *)str);

 The second way is to use the precision specifier. The way D arrays are

 the length comes first, so the following works:

 printf("the string is '%.*s'\n", str);
 ______________________________
 I just want to say that the first described above way is not compiled


 failed
 with an error (see my first message).

 In article <bgo3ds$101p$1 digitaldaemon.com>, Matthew Wilson says...
Sorry, I don't understand. In your example you said you done "%s",


I'm saying you must use "%.*s". If indeed you used "%.*s" then it's out


my jurisdiction, I'm afraid. ;)

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnte9$qg8$1 digitaldaemon.com...
 That's the way I implemented it, but what about the spec?

 In article <bgnsh5$pk3$1 digitaldaemon.com>, Matthew Wilson says...
Use %.*s for the string format specifier

"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.







Aug 05 2003
prev sibling next sibling parent Paul Runde <prunde consolidated.net> writes:
Gennadi Pais wrote:
 Hi All,
 during my first trying of the D language in the code:
 
 char[] str = "blah-blah";
 str.append(0);
 printf ("str is: %s\n", str);
 
 I received compiler error:
 .. undefined identifier append
 
 Compiler is: Digital Mars D Compiler Beta v0.68
 
 The tested code is from the D spec.
 Thanks.
 
 

From html/d/arrays.html " Since strings, however, are not 0 terminated in D, when transfering a pointer to a string to C, add a terminating 0: str.append(0); " However, append is not listed as an array property. Try this: import string; char[] str = "blah-blah"; printf ("str is: %s\n", toStringz(str)); toStringz appends the terminator. Paul
Aug 05 2003
prev sibling next sibling parent "Mike Wynn" <mike.wynn l8night.co.uk> writes:
"Gennadi Pais" <Gennadi_member pathlink.com> wrote in message
news:bgnqjm$nsb$1 digitaldaemon.com...
 Hi All,
 during my first trying of the D language in the code:

 char[] str = "blah-blah";
 str.append(0);

 printf ("str is: %s\n", str);

 I received compiler error:
 .. undefined identifier append

 Compiler is: Digital Mars D Compiler Beta v0.68

 The tested code is from the D spec.
 Thanks.

char[] str = "blah-blah"; printf ("str is: %.*s\n", str); "%.*s" is the D string format spec. if you want to append to a string use operator ~ str = str ~ "\0"; or str = str ~ \0; /// note no ' ' as you would in C.
Aug 05 2003
prev sibling parent "Walter" <walter digitalmars.com> writes:
Thanks for pointing this out. I've corrected the spec.
Sep 12 2003